How-many-pairs-of-2-numbers-are-there-whose-LCM-is-N

If N= a^m*b^n *c^o then ordered solution such that LCM = N is (2m+1)*(2n+1)*(2o+1)
Unordered will be (2m+1)*(2n+1)*(2o+1) /2 +0.5