Which is the Smallest number that has 4 prime factors & 48 total factors?
Take first 4 prime numbers as
2^a*3^b*5^c*7^d
Give maximum powers to 2 and 3 to get the minimum number
(a+1)(b+1)(c+1)(d+1)=48
4*3*2*2=48
a=3 b=2 c=1 d=1
8*9*5*7=2520 Ans.
2^a*3^b*5^c*7^d
Give maximum powers to 2 and 3 to get the minimum number
(a+1)(b+1)(c+1)(d+1)=48
4*3*2*2=48
a=3 b=2 c=1 d=1
8*9*5*7=2520 Ans.
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